Chemical properties of Neodymium

The salts of neodymium are rose-red or reddish-violet in colour, and the absorption spectra of their aqueous solutions show characteristic absorption bands. The following equivalent conductivity determinations (λ), effected at 25°, show that the salts are derived from a fairly strong triacid base (v = dilution in litres per gram equivalent): -

NdCl3	v=	29.28	58.56	117.12	234.24	468.48	936.96
	λ=	103.0	110.9	118.85	124.1	128.7	133.4
Nd2(SO4)3	v=	33.47	66.94	133.88	267.76	535.52	1071.04
	λ=	40.61	48.15	47.12(?)	62.23	80.21	95.95
Nd(C2H3O2)3	v=	33.81	67.62	135.24	270.48	540.96	1081.92
	λ=	42.43	50.28	58.55	67.66	76.81	86.89

The following results have been recorded: -

2[Nd] + 3(O) = [Nd₂O₃] + 435.1 Cals
2[Nd] + 3[S] = [Nd₂S₃] + 285.9 Cals
[Nd] + 3(Cl) = [NdCl₃] + 249.5 Cals
[Nd] + 3[I] = [NdI₃] + 157.7 Cals
2[Nd] + 3[S] + 6(O₂) = [Nd₂(SO₄)] + 928.2 Cals
2[Nd] + 3[S] + 6(O₂) + 8[H₂O] = [Nd₂(SO₄)₃.8H₂O] + 946.8 Cals
NdCl₃] + Aq. = NdCl₃aq + 35.4 Cals
[NdCl₃.6H₂O] + Aq. = NdCl₃aq. + 7.6 Cals
[NdI₃] + Aq. = NdI₃aq + 48.9 Cals
[Nd₂(SO₄)₃] + Aq. = Nd₂(SO₄)₃aq + 36.5 Cals
[Nd₂(SO₄)₃.5H₂O] + Aq. = Nd₂(SO₄)₃aq + 8.3 Cals
[Nd₂(SO₄)₃.8H₂O] + Aq. = Nd₂(SO₄)₃aq + 6.7 Cals
[NdCl₃] + alcohol = NdCl₃ in alc. soln. + 21.5 Cals
[Nd₂O₃] + 6HClaq. = 2NdCl₃aq. + 3H₂O + 105.5 Cals
[Nd₂O₃] + 6HIaq. = 2NdI₃aq. + 3H₂O + 106.1 Cals
[Nd₂O₃] + 3[H₂SO₄] = [Nd₂(SO₄)₃] + 3H₂O + 125.1 Cals
[Nd₂O₃] + 3H₂SO₄aq. = Nd₂(SO₄)₃aq. + 3H₂O + 106.4 Cals